154033341131 has 4 divisors (see below), whose sum is σ = 154034557200. Its totient is φ = 154032125064.

The previous prime is 154033341127. The next prime is 154033341139. The reversal of 154033341131 is 131143330451.

It is a happy number.

154033341131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 154033341131 - 2² = 154033341127 is a prime.

It is a super-2 number, since 2×154033341131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 154033341094 and 154033341103.

It is not an unprimeable number, because it can be changed into a prime (154033341139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 392591 + ... + 679848.

It is an arithmetic number, because the mean of its divisors is an integer number (38508639300).

Almost surely, 2^154033341131 is an apocalyptic number.

154033341131 is a deficient number, since it is larger than the sum of its proper divisors (1216069).

154033341131 is a wasteful number, since it uses less digits than its factorization.

154033341131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1216068.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 154033341131 its reverse (131143330451), we get a palindrome (285176671582).

The spelling of 154033341131 in words is "one hundred fifty-four billion, thirty-three million, three hundred forty-one thousand, one hundred thirty-one".