Base | Representation |
---|---|
bin | 10110011010101001110… |
… | …001110010101100000011 |
3 | 12110021011101020002101201 |
4 | 112122221301302230003 |
5 | 200214313323203042 |
6 | 3135401010442031 |
7 | 216202463566444 |
oct | 26325161625403 |
9 | 5407141202351 |
10 | 1540446694147 |
11 | 544332aaa349 |
12 | 20a670593317 |
13 | b2356ba8c1a |
14 | 547b52b52cb |
15 | 2a10d1ba1b7 |
hex | 166a9c72b03 |
1540446694147 has 2 divisors, whose sum is σ = 1540446694148. Its totient is φ = 1540446694146.
The previous prime is 1540446694097. The next prime is 1540446694159. The reversal of 1540446694147 is 7414966440451.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1540446694147 is a prime.
It is a super-3 number, since 3×15404466941473 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1540446694847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770223347073 + 770223347074.
It is an arithmetic number, because the mean of its divisors is an integer number (770223347074).
Almost surely, 21540446694147 is an apocalyptic number.
1540446694147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1540446694147 is an equidigital number, since it uses as much as digits as its factorization.
1540446694147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11612160, while the sum is 55.
The spelling of 1540446694147 in words is "one trillion, five hundred forty billion, four hundred forty-six million, six hundred ninety-four thousand, one hundred forty-seven".
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