Search a number
-
+
154045433 is a prime number
BaseRepresentation
bin10010010111010…
…00101111111001
3101201212022121102
421023220233321
5303413423213
623141421145
73550236023
oct1113505771
9351768542
10154045433
1179a55683
124370a7b5
1325bb7359
141665d013
15d7cd158
hex92e8bf9

154045433 has 2 divisors, whose sum is σ = 154045434. Its totient is φ = 154045432.

The previous prime is 154045373. The next prime is 154045457. The reversal of 154045433 is 334540451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 142969849 + 11075584 = 11957^2 + 3328^2 .

It is a cyclic number.

It is not a de Polignac number, because 154045433 - 212 = 154041337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 154045396 and 154045405.

It is not a weakly prime, because it can be changed into another prime (154045933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77022716 + 77022717.

It is an arithmetic number, because the mean of its divisors is an integer number (77022717).

Almost surely, 2154045433 is an apocalyptic number.

It is an amenable number.

154045433 is a deficient number, since it is larger than the sum of its proper divisors (1).

154045433 is an equidigital number, since it uses as much as digits as its factorization.

154045433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 29.

The square root of 154045433 is about 12411.5040587352. The cubic root of 154045433 is about 536.0635471271.

Adding to 154045433 its reverse (334540451), we get a palindrome (488585884).

The spelling of 154045433 in words is "one hundred fifty-four million, forty-five thousand, four hundred thirty-three".