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154140000000 = 283577367
BaseRepresentation
bin1000111110001101110…
…1011011111100000000
3112201212021121022012220
42033203131123330000
510011134320000000
6154451055051040
714064506245050
oct2174335337400
9481767538186
10154140000000
115a409014458
1225a59210a80
13116c61ab1bc
147663549560
1540222ab1a0
hex23e375bf00

154140000000 has 576 divisors, whose sum is σ = 587648495616. Its totient is φ = 35136000000.

The previous prime is 154139999983. The next prime is 154140000019. The reversal of 154140000000 is 41451.

It is a super-3 number, since 3×1541400000003 (a number of 35 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 419999817 + ... + 420000183.

Almost surely, 2154140000000 is an apocalyptic number.

154140000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 154140000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (293824247808).

154140000000 is an abundant number, since it is smaller than the sum of its proper divisors (433508495616).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

154140000000 is an frugal number, since it uses more digits than its factorization.

154140000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 428 (or 384 counting only the distinct ones).

The product of its (nonzero) digits is 80, while the sum is 15.

Adding to 154140000000 its reverse (41451), we get a palindrome (154140041451).

The spelling of 154140000000 in words is "one hundred fifty-four billion, one hundred forty million", and thus it is an aban number.