Base | Representation |
---|---|
bin | 10110011011100011110… |
… | …110101000001110010011 |
3 | 12110100200021122000100211 |
4 | 112123203312220032103 |
5 | 200223312241244111 |
6 | 3140041414224551 |
7 | 216235564443451 |
oct | 26334366501623 |
9 | 5410607560324 |
10 | 1541421040531 |
11 | 544792aa1199 |
12 | 20a8a2955157 |
13 | b2480a03548 |
14 | 548688659d1 |
15 | 2a1689d0521 |
hex | 166e3da8393 |
1541421040531 has 2 divisors, whose sum is σ = 1541421040532. Its totient is φ = 1541421040530.
The previous prime is 1541421040499. The next prime is 1541421040541. The reversal of 1541421040531 is 1350401241451.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1541421040531 - 25 = 1541421040499 is a prime.
It is a super-2 number, since 2×15414210405312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1541421040493 and 1541421040502.
It is not a weakly prime, because it can be changed into another prime (1541421040541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770710520265 + 770710520266.
It is an arithmetic number, because the mean of its divisors is an integer number (770710520266).
Almost surely, 21541421040531 is an apocalyptic number.
1541421040531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1541421040531 is an equidigital number, since it uses as much as digits as its factorization.
1541421040531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1541421040531 its reverse (1350401241451), we get a palindrome (2891822281982).
The spelling of 1541421040531 in words is "one trillion, five hundred forty-one billion, four hundred twenty-one million, forty thousand, five hundred thirty-one".
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