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154200224505553 is a prime number
BaseRepresentation
bin100011000011111010001001…
…100110110001111011010001
3202012222101201202220020120121
4203003322021212301323101
5130202404024433134203
61303542334420110241
744323412212033612
oct4303721146617321
9665871652806517
10154200224505553
1145150a47818406
1215365053235381
13680703233ac25
142a1148b59bc09
1512c617d4090bd
hex8c3e899b1ed1

154200224505553 has 2 divisors, whose sum is σ = 154200224505554. Its totient is φ = 154200224505552.

The previous prime is 154200224505461. The next prime is 154200224505557. The reversal of 154200224505553 is 355505422002451.

154200224505553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90470211165889 + 63730013339664 = 9511583^2 + 7983108^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-154200224505553 is a prime.

It is not a weakly prime, because it can be changed into another prime (154200224505557) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77100112252776 + 77100112252777.

It is an arithmetic number, because the mean of its divisors is an integer number (77100112252777).

Almost surely, 2154200224505553 is an apocalyptic number.

It is an amenable number.

154200224505553 is a deficient number, since it is larger than the sum of its proper divisors (1).

154200224505553 is an equidigital number, since it uses as much as digits as its factorization.

154200224505553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200000, while the sum is 43.

The spelling of 154200224505553 in words is "one hundred fifty-four trillion, two hundred billion, two hundred twenty-four million, five hundred five thousand, five hundred fifty-three".