Base | Representation |
---|---|
bin | 1000111110011100011… |
… | …0010101011110111001 |
3 | 112202000112111010100022 |
4 | 2033213012111132321 |
5 | 10011300432144423 |
6 | 154501115420225 |
7 | 14066150216342 |
oct | 2174706253671 |
9 | 482015433308 |
10 | 154201053113 |
11 | 5a43a524578 |
12 | 25a75754675 |
13 | 11705a365c3 |
14 | 766b6bd0c9 |
15 | 402781adc8 |
hex | 23e71957b9 |
154201053113 has 2 divisors, whose sum is σ = 154201053114. Its totient is φ = 154201053112.
The previous prime is 154201053101. The next prime is 154201053131. The reversal of 154201053113 is 311350102451.
Together with next prime (154201053131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129839150224 + 24361902889 = 360332^2 + 156083^2 .
It is a cyclic number.
It is not a de Polignac number, because 154201053113 - 214 = 154201036729 is a prime.
It is not a weakly prime, because it can be changed into another prime (154201053143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77100526556 + 77100526557.
It is an arithmetic number, because the mean of its divisors is an integer number (77100526557).
Almost surely, 2154201053113 is an apocalyptic number.
It is an amenable number.
154201053113 is a deficient number, since it is larger than the sum of its proper divisors (1).
154201053113 is an equidigital number, since it uses as much as digits as its factorization.
154201053113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 154201053113 its reverse (311350102451), we get a palindrome (465551155564).
The spelling of 154201053113 in words is "one hundred fifty-four billion, two hundred one million, fifty-three thousand, one hundred thirteen".
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