Base | Representation |
---|---|
bin | 11100101110001110… |
… | …01110001001001001 |
3 | 1110210122202000020011 |
4 | 32113013032021021 |
5 | 223040024420231 |
6 | 11030043231521 |
7 | 1054061102326 |
oct | 162707161111 |
9 | 43718660204 |
10 | 15420154441 |
11 | 65a330329a |
12 | 2ba42185a1 |
13 | 15b98c6153 |
14 | a63d53b4d |
15 | 603b599b1 |
hex | 3971ce249 |
15420154441 has 2 divisors, whose sum is σ = 15420154442. Its totient is φ = 15420154440.
The previous prime is 15420154429. The next prime is 15420154481. The reversal of 15420154441 is 14445102451.
15420154441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15277948816 + 142205625 = 123604^2 + 11925^2 .
It is a cyclic number.
It is not a de Polignac number, because 15420154441 - 217 = 15420023369 is a prime.
It is not a weakly prime, because it can be changed into another prime (15420154481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7710077220 + 7710077221.
It is an arithmetic number, because the mean of its divisors is an integer number (7710077221).
Almost surely, 215420154441 is an apocalyptic number.
It is an amenable number.
15420154441 is a deficient number, since it is larger than the sum of its proper divisors (1).
15420154441 is an equidigital number, since it uses as much as digits as its factorization.
15420154441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 15420154441 its reverse (14445102451), we get a palindrome (29865256892).
The spelling of 15420154441 in words is "fifteen billion, four hundred twenty million, one hundred fifty-four thousand, four hundred forty-one".
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