Base | Representation |
---|---|
bin | 10010011000100… |
… | …01100001011010 |
3 | 101202011210200221 |
4 | 21030101201122 |
5 | 303434244232 |
6 | 23145150254 |
7 | 3551532646 |
oct | 1114214132 |
9 | 352153627 |
10 | 154212442 |
11 | 7a05a0aa |
12 | 4378b38a |
13 | 25c45387 |
14 | 166a3c26 |
15 | d812897 |
hex | 931185a |
154212442 has 4 divisors (see below), whose sum is σ = 231318666. Its totient is φ = 77106220.
The previous prime is 154212433. The next prime is 154212449. The reversal of 154212442 is 244212451.
154212442 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 99022401 + 55190041 = 9951^2 + 7429^2 .
It is not an unprimeable number, because it can be changed into a prime (154212449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38553109 + ... + 38553112.
Almost surely, 2154212442 is an apocalyptic number.
154212442 is a deficient number, since it is larger than the sum of its proper divisors (77106224).
154212442 is an equidigital number, since it uses as much as digits as its factorization.
154212442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77106223.
The product of its digits is 2560, while the sum is 25.
The square root of 154212442 is about 12418.2302281766. The cubic root of 154212442 is about 536.2572023382.
Adding to 154212442 its reverse (244212451), we get a palindrome (398424893).
Subtracting 154212442 from its reverse (244212451), we obtain a palindrome (90000009).
The spelling of 154212442 in words is "one hundred fifty-four million, two hundred twelve thousand, four hundred forty-two".
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