Base | Representation |
---|---|
bin | 1000111111010000110… |
… | …1111001101101101011 |
3 | 112202120212121201020202 |
4 | 2033310031321231223 |
5 | 10012223302442311 |
6 | 154535020542415 |
7 | 14104462015133 |
oct | 2176415715553 |
9 | 482525551222 |
10 | 154421140331 |
11 | 5a542787337 |
12 | 25b173b1a0b |
13 | 1173c504923 |
14 | 768ca0dac3 |
15 | 403bce1e3b |
hex | 23f4379b6b |
154421140331 has 2 divisors, whose sum is σ = 154421140332. Its totient is φ = 154421140330.
The previous prime is 154421140277. The next prime is 154421140387. The reversal of 154421140331 is 133041124451.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-154421140331 is a prime.
It is a super-2 number, since 2×1544211403312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 154421140294 and 154421140303.
It is not a weakly prime, because it can be changed into another prime (154421142331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77210570165 + 77210570166.
It is an arithmetic number, because the mean of its divisors is an integer number (77210570166).
Almost surely, 2154421140331 is an apocalyptic number.
154421140331 is a deficient number, since it is larger than the sum of its proper divisors (1).
154421140331 is an equidigital number, since it uses as much as digits as its factorization.
154421140331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 154421140331 its reverse (133041124451), we get a palindrome (287462264782).
The spelling of 154421140331 in words is "one hundred fifty-four billion, four hundred twenty-one million, one hundred forty thousand, three hundred thirty-one".
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