Base | Representation |
---|---|
bin | 1001000001001110001… |
… | …0100001101001000011 |
3 | 112210221111102212220011 |
4 | 2100103202201221003 |
5 | 10014312314443301 |
6 | 155103112125351 |
7 | 14123502466351 |
oct | 2202342415103 |
9 | 483844385804 |
10 | 154946640451 |
11 | 5a792380359 |
12 | 26043396857 |
13 | 117c4347745 |
14 | 76dc7227d1 |
15 | 406cee5a51 |
hex | 24138a1a43 |
154946640451 has 2 divisors, whose sum is σ = 154946640452. Its totient is φ = 154946640450.
The previous prime is 154946640439. The next prime is 154946640493. The reversal of 154946640451 is 154046649451.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 154946640451 - 27 = 154946640323 is a prime.
It is a super-2 number, since 2×1549466404512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 154946640395 and 154946640404.
It is not a weakly prime, because it can be changed into another prime (154946610451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77473320225 + 77473320226.
It is an arithmetic number, because the mean of its divisors is an integer number (77473320226).
Almost surely, 2154946640451 is an apocalyptic number.
154946640451 is a deficient number, since it is larger than the sum of its proper divisors (1).
154946640451 is an equidigital number, since it uses as much as digits as its factorization.
154946640451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2073600, while the sum is 49.
The spelling of 154946640451 in words is "one hundred fifty-four billion, nine hundred forty-six million, six hundred forty thousand, four hundred fifty-one".
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