Base | Representation |
---|---|
bin | 100011001111101000000101… |
… | …000111110000101110110011 |
3 | 202022211101011201022210211111 |
4 | 203033220011013300232303 |
5 | 130304102133120231311 |
6 | 1305400305005454151 |
7 | 44435526455504212 |
oct | 4317500507605663 |
9 | 668741151283744 |
10 | 155005455633331 |
11 | 454314987a28a6 |
12 | 15475119571357 |
13 | 6864c4acab884 |
14 | 2a3c43858b079 |
15 | 12dc0aaaa9d21 |
hex | 8cfa051f0bb3 |
155005455633331 has 2 divisors, whose sum is σ = 155005455633332. Its totient is φ = 155005455633330.
The previous prime is 155005455633307. The next prime is 155005455633389. The reversal of 155005455633331 is 133336554500551.
155005455633331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 155005455633331 - 215 = 155005455600563 is a prime.
It is a super-2 number, since 2×1550054556333312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (155005455673331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77502727816665 + 77502727816666.
It is an arithmetic number, because the mean of its divisors is an integer number (77502727816666).
Almost surely, 2155005455633331 is an apocalyptic number.
155005455633331 is a deficient number, since it is larger than the sum of its proper divisors (1).
155005455633331 is an equidigital number, since it uses as much as digits as its factorization.
155005455633331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6075000, while the sum is 49.
The spelling of 155005455633331 in words is "one hundred fifty-five trillion, five billion, four hundred fifty-five million, six hundred thirty-three thousand, three hundred thirty-one".
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