Base | Representation |
---|---|
bin | 10110100011101011001… |
… | …101001110110001111011 |
3 | 12111012011112020112012001 |
4 | 112203223031032301323 |
5 | 200344133342400411 |
6 | 3144042154401431 |
7 | 216664526331154 |
oct | 26435315166173 |
9 | 5435145215161 |
10 | 1550134340731 |
11 | 548454472639 |
12 | 210514a30277 |
13 | b323bc61792 |
14 | 55053b6a92b |
15 | 2a4c8928dc1 |
hex | 168eb34ec7b |
1550134340731 has 2 divisors, whose sum is σ = 1550134340732. Its totient is φ = 1550134340730.
The previous prime is 1550134340723. The next prime is 1550134340743. The reversal of 1550134340731 is 1370434310551.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1550134340731 - 23 = 1550134340723 is a prime.
It is a super-2 number, since 2×15501343407312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1550134340761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775067170365 + 775067170366.
It is an arithmetic number, because the mean of its divisors is an integer number (775067170366).
Almost surely, 21550134340731 is an apocalyptic number.
1550134340731 is a deficient number, since it is larger than the sum of its proper divisors (1).
1550134340731 is an equidigital number, since it uses as much as digits as its factorization.
1550134340731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 37.
The spelling of 1550134340731 in words is "one trillion, five hundred fifty billion, one hundred thirty-four million, three hundred forty thousand, seven hundred thirty-one".
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