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155054133044 = 22119393246799
BaseRepresentation
bin1001000001100111110…
…0100100111100110100
3112211012222201002000022
42100121330210330310
510020022324224134
6155121512104312
714126246246006
oct2203174447464
9484188632008
10155054133044
115a83801a108
1226073395098
13118106b2725
14770cb04376
15407767a52e
hex2419f24f34

155054133044 has 12 divisors (see below), whose sum is σ = 271367544000. Its totient is φ = 77520549048.

The previous prime is 155054133023. The next prime is 155054133097. The reversal of 155054133044 is 440331450551.

It is a super-3 number, since 3×1550541330443 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 155054132995 and 155054133013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1575644 + ... + 1671155.

It is an arithmetic number, because the mean of its divisors is an integer number (22613962000).

Almost surely, 2155054133044 is an apocalyptic number.

It is an amenable number.

155054133044 is a deficient number, since it is larger than the sum of its proper divisors (116313410956).

155054133044 is a wasteful number, since it uses less digits than its factorization.

155054133044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3258742 (or 3258740 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 155054133044 its reverse (440331450551), we get a palindrome (595385583595).

The spelling of 155054133044 in words is "one hundred fifty-five billion, fifty-four million, one hundred thirty-three thousand, forty-four".

Divisors: 1 2 4 11939 23878 47756 3246799 6493598 12987196 38763533261 77527066522 155054133044