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1551253271017 is a prime number
BaseRepresentation
bin10110100100101101111…
…001100111000111101001
312111022001111201001222111
4112210231321213013221
5200403431314133032
63144345205122321
7220034334146452
oct26445571470751
95438044631874
101551253271017
1154897903750a
122107876b93a1
13b3389a0c9c8
145511c5d6129
152a541c9dc47
hex1692de671e9

1551253271017 has 2 divisors, whose sum is σ = 1551253271018. Its totient is φ = 1551253271016.

The previous prime is 1551253270961. The next prime is 1551253271033. The reversal of 1551253271017 is 7101723521551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1544591609856 + 6661661161 = 1242816^2 + 81619^2 .

It is an emirp because it is prime and its reverse (7101723521551) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1551253271017 is a prime.

It is not a weakly prime, because it can be changed into another prime (1551253271047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775626635508 + 775626635509.

It is an arithmetic number, because the mean of its divisors is an integer number (775626635509).

Almost surely, 21551253271017 is an apocalyptic number.

It is an amenable number.

1551253271017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1551253271017 is an equidigital number, since it uses as much as digits as its factorization.

1551253271017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 73500, while the sum is 40.

Adding to 1551253271017 its reverse (7101723521551), we get a palindrome (8652976792568).

The spelling of 1551253271017 in words is "one trillion, five hundred fifty-one billion, two hundred fifty-three million, two hundred seventy-one thousand, seventeen".