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155143346323561 is a prime number
BaseRepresentation
bin100011010001101000100000…
…000011000000000001101001
3202100022120002112222122112121
4203101220200003000001221
5130313332033124323221
61305543511441511241
744451510515153311
oct4321504003000151
9670276075878477
10155143346323561
1145484a1846a322
12154979a0942521
136874c5487337b
142a44d999c8441
1512e097b525a41
hex8d1a200c0069

155143346323561 has 2 divisors, whose sum is σ = 155143346323562. Its totient is φ = 155143346323560.

The previous prime is 155143346323519. The next prime is 155143346323571. The reversal of 155143346323561 is 165323643341551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 144789334728336 + 10354011595225 = 12032844^2 + 3217765^2 .

It is a cyclic number.

It is not a de Polignac number, because 155143346323561 - 213 = 155143346315369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 155143346323499 and 155143346323508.

It is not a weakly prime, because it can be changed into another prime (155143346323571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77571673161780 + 77571673161781.

It is an arithmetic number, because the mean of its divisors is an integer number (77571673161781).

Almost surely, 2155143346323561 is an apocalyptic number.

It is an amenable number.

155143346323561 is a deficient number, since it is larger than the sum of its proper divisors (1).

155143346323561 is an equidigital number, since it uses as much as digits as its factorization.

155143346323561 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11664000, while the sum is 52.

The spelling of 155143346323561 in words is "one hundred fifty-five trillion, one hundred forty-three billion, three hundred forty-six million, three hundred twenty-three thousand, five hundred sixty-one".