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1552551140423 = 1981713217917
BaseRepresentation
bin10110100101111011010…
…000100101110001000111
312111102101221212200002202
4112211323100211301013
5200414111042443143
63145122051025115
7220111443644333
oct26457320456107
95442357780082
101552551140423
11549484709a58
12210a8a29b19b
13b353587cc7a
1455202b207c3
152a5babbcab8
hex1697b425c47

1552551140423 has 4 divisors (see below), whose sum is σ = 1634264358360. Its totient is φ = 1470837922488.

The previous prime is 1552551140417. The next prime is 1552551140449. The reversal of 1552551140423 is 3240411552551.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1552551140423 - 218 = 1552550878279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1552551140473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40856608940 + ... + 40856608977.

It is an arithmetic number, because the mean of its divisors is an integer number (408566089590).

Almost surely, 21552551140423 is an apocalyptic number.

1552551140423 is a deficient number, since it is larger than the sum of its proper divisors (81713217937).

1552551140423 is an equidigital number, since it uses as much as digits as its factorization.

1552551140423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81713217936.

The product of its (nonzero) digits is 120000, while the sum is 38.

Adding to 1552551140423 its reverse (3240411552551), we get a palindrome (4792962692974).

The spelling of 1552551140423 in words is "one trillion, five hundred fifty-two billion, five hundred fifty-one million, one hundred forty thousand, four hundred twenty-three".

Divisors: 1 19 81713217917 1552551140423