Search a number
-
+
1553000113551 = 3517666704517
BaseRepresentation
bin10110100110010110000…
…001010010010110001111
312111110120020200212110010
4112212112001102112033
5200421021012113201
63145234410044303
7220125535106025
oct26462601222617
95443506625403
101553000113551
11549695094127
12210b94719693
13b35a78aa443
14552465d2715
152a5e5306bd6
hex1699605258f

1553000113551 has 4 divisors (see below), whose sum is σ = 2070666818072. Its totient is φ = 1035333409032.

The previous prime is 1553000113549. The next prime is 1553000113579. The reversal of 1553000113551 is 1553110003551.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1553000113551 - 21 = 1553000113549 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1553000113351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258833352256 + ... + 258833352261.

It is an arithmetic number, because the mean of its divisors is an integer number (517666704518).

Almost surely, 21553000113551 is an apocalyptic number.

1553000113551 is a deficient number, since it is larger than the sum of its proper divisors (517666704521).

1553000113551 is an equidigital number, since it uses as much as digits as its factorization.

1553000113551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 517666704520.

The product of its (nonzero) digits is 5625, while the sum is 30.

The spelling of 1553000113551 in words is "one trillion, five hundred fifty-three billion, one hundred thirteen thousand, five hundred fifty-one".

Divisors: 1 3 517666704517 1553000113551