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155300053413 = 351766684471
BaseRepresentation
bin1001000010100010011…
…0101100000110100101
3112211212010110010100010
42100220212230012211
510021023303202123
6155202135040433
714135323450011
oct2205046540645
9484763403303
10155300053413
115a95391678a
1226121810119
131184c62723b
14773363b541
15408e055993
hex24289ac1a5

155300053413 has 4 divisors (see below), whose sum is σ = 207066737888. Its totient is φ = 103533368940.

The previous prime is 155300053393. The next prime is 155300053429. The reversal of 155300053413 is 314350003551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 155300053413 - 216 = 155299987877 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155300053613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25883342233 + ... + 25883342238.

It is an arithmetic number, because the mean of its divisors is an integer number (51766684472).

Almost surely, 2155300053413 is an apocalyptic number.

It is an amenable number.

155300053413 is a deficient number, since it is larger than the sum of its proper divisors (51766684475).

155300053413 is an equidigital number, since it uses as much as digits as its factorization.

155300053413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51766684474.

The product of its (nonzero) digits is 13500, while the sum is 30.

Adding to 155300053413 its reverse (314350003551), we get a palindrome (469650056964).

The spelling of 155300053413 in words is "one hundred fifty-five billion, three hundred million, fifty-three thousand, four hundred thirteen".

Divisors: 1 3 51766684471 155300053413