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1553401432001 is a prime number
BaseRepresentation
bin10110100110101101111…
…100001100011111000001
312111111121012211221212102
4112212231330030133001
5200422331231311001
63145342303440145
7220141510211456
oct26465574143701
95444535757772
101553401432001
1154988067a671
12211086bb6055
13b363ca90b93
1455283a1b82d
152a61a67ae6b
hex169adf0c7c1

1553401432001 has 2 divisors, whose sum is σ = 1553401432002. Its totient is φ = 1553401432000.

The previous prime is 1553401431877. The next prime is 1553401432007. The reversal of 1553401432001 is 1002341043551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1286681862400 + 266719569601 = 1134320^2 + 516449^2 .

It is an emirp because it is prime and its reverse (1002341043551) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1553401432001 - 238 = 1278523525057 is a prime.

It is a super-3 number, since 3×15534014320013 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1553401432007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776700716000 + 776700716001.

It is an arithmetic number, because the mean of its divisors is an integer number (776700716001).

Almost surely, 21553401432001 is an apocalyptic number.

It is an amenable number.

1553401432001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1553401432001 is an equidigital number, since it uses as much as digits as its factorization.

1553401432001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 1553401432001 its reverse (1002341043551), we get a palindrome (2555742475552).

The spelling of 1553401432001 in words is "one trillion, five hundred fifty-three billion, four hundred one million, four hundred thirty-two thousand, one".