Base | Representation |
---|---|
bin | 1001000010111100111… |
… | …1001011010000000111 |
3 | 112212010212211120012020 |
4 | 2100233033023100013 |
5 | 10021240300030210 |
6 | 155221152054223 |
7 | 14141144336502 |
oct | 2205717132007 |
9 | 485125746166 |
10 | 155411330055 |
11 | 5aa0070a553 |
12 | 26152b34373 |
13 | 118696b86c7 |
14 | 7744326139 |
15 | 4098bd6770 |
hex | 242f3cb407 |
155411330055 has 8 divisors (see below), whose sum is σ = 248658128112. Its totient is φ = 82886042688.
The previous prime is 155411330023. The next prime is 155411330057. The reversal of 155411330055 is 550033114551.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 155411330055 - 25 = 155411330023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 155411329998 and 155411330025.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (155411330057) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5180377654 + ... + 5180377683.
It is an arithmetic number, because the mean of its divisors is an integer number (31082266014).
Almost surely, 2155411330055 is an apocalyptic number.
155411330055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
155411330055 is a deficient number, since it is larger than the sum of its proper divisors (93246798057).
155411330055 is a wasteful number, since it uses less digits than its factorization.
155411330055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10360755345.
The product of its (nonzero) digits is 22500, while the sum is 33.
The spelling of 155411330055 in words is "one hundred fifty-five billion, four hundred eleven million, three hundred thirty thousand, fifty-five".
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