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155411330057 is a prime number
BaseRepresentation
bin1001000010111100111…
…1001011010000001001
3112212010212211120012022
42100233033023100021
510021240300030212
6155221152054225
714141144336504
oct2205717132011
9485125746168
10155411330057
115aa0070a555
1226152b34375
13118696b86c9
14774432613b
154098bd6772
hex242f3cb409

155411330057 has 2 divisors, whose sum is σ = 155411330058. Its totient is φ = 155411330056.

The previous prime is 155411330023. The next prime is 155411330069. The reversal of 155411330057 is 750033114551.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 152170988281 + 3240341776 = 390091^2 + 56924^2 .

It is a cyclic number.

It is not a de Polignac number, because 155411330057 - 26 = 155411329993 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 155411329999 and 155411330026.

It is not a weakly prime, because it can be changed into another prime (155411330857) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77705665028 + 77705665029.

It is an arithmetic number, because the mean of its divisors is an integer number (77705665029).

Almost surely, 2155411330057 is an apocalyptic number.

It is an amenable number.

155411330057 is a deficient number, since it is larger than the sum of its proper divisors (1).

155411330057 is an equidigital number, since it uses as much as digits as its factorization.

155411330057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31500, while the sum is 35.

The spelling of 155411330057 in words is "one hundred fifty-five billion, four hundred eleven million, three hundred thirty thousand, fifty-seven".