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155434440013339 is a prime number
BaseRepresentation
bin100011010101110111100110…
…100101010011011000011011
3202101100101110101010020111011
4203111313212211103120123
5130333114213120411324
61310325332421514351
744511524215535644
oct4325674645233033
9671311411106434
10155434440013339
1145587415246963
121552429b5729b7
136896535466216
142a550d1d426cb
1512e8316d62c94
hex8d5de695361b

155434440013339 has 2 divisors, whose sum is σ = 155434440013340. Its totient is φ = 155434440013338.

The previous prime is 155434440013297. The next prime is 155434440013379. The reversal of 155434440013339 is 933310044434551.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 155434440013339 - 27 = 155434440013211 is a prime.

It is a super-3 number, since 3×1554344400133393 (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 155434440013292 and 155434440013301.

It is not a weakly prime, because it can be changed into another prime (155434440013379) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77717220006669 + 77717220006670.

It is an arithmetic number, because the mean of its divisors is an integer number (77717220006670).

Almost surely, 2155434440013339 is an apocalyptic number.

155434440013339 is a deficient number, since it is larger than the sum of its proper divisors (1).

155434440013339 is an equidigital number, since it uses as much as digits as its factorization.

155434440013339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4665600, while the sum is 49.

The spelling of 155434440013339 in words is "one hundred fifty-five trillion, four hundred thirty-four billion, four hundred forty million, thirteen thousand, three hundred thirty-nine".