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15550117003 is a prime number
BaseRepresentation
bin11100111101101101…
…11111010010001011
31111010201021210100101
432132312333102023
5223321312221003
611051004550231
71060226546041
oct163666772213
944121253311
1015550117003
11665a6aa073
12301b852377
13160a7ca885
14a77304391
1561027c11d
hex39edbf48b

15550117003 has 2 divisors, whose sum is σ = 15550117004. Its totient is φ = 15550117002.

The previous prime is 15550116919. The next prime is 15550117013. The reversal of 15550117003 is 30071105551.

It is a strong prime.

It is an emirp because it is prime and its reverse (30071105551) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15550117003 - 217 = 15549985931 is a prime.

It is a super-2 number, since 2×155501170032 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15550117013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7775058501 + 7775058502.

It is an arithmetic number, because the mean of its divisors is an integer number (7775058502).

Almost surely, 215550117003 is an apocalyptic number.

15550117003 is a deficient number, since it is larger than the sum of its proper divisors (1).

15550117003 is an equidigital number, since it uses as much as digits as its factorization.

15550117003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2625, while the sum is 28.

The spelling of 15550117003 in words is "fifteen billion, five hundred fifty million, one hundred seventeen thousand, three".