Base | Representation |
---|---|
bin | 1001000011010010110… |
… | …1110000110001100011 |
3 | 112212101021202202220111 |
4 | 2100310231300301203 |
5 | 10021432311443042 |
6 | 155234233552151 |
7 | 14143341452452 |
oct | 2206455606143 |
9 | 485337682814 |
10 | 155503234147 |
11 | 5aa48581448 |
12 | 26179875657 |
13 | 11882756221 |
14 | 775260ab99 |
15 | 40a1cdc517 |
hex | 2434b70c63 |
155503234147 has 2 divisors, whose sum is σ = 155503234148. Its totient is φ = 155503234146.
The previous prime is 155503234121. The next prime is 155503234153. The reversal of 155503234147 is 741432305551.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-155503234147 is a prime.
It is not a weakly prime, because it can be changed into another prime (155503234247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77751617073 + 77751617074.
It is an arithmetic number, because the mean of its divisors is an integer number (77751617074).
Almost surely, 2155503234147 is an apocalyptic number.
155503234147 is a deficient number, since it is larger than the sum of its proper divisors (1).
155503234147 is an equidigital number, since it uses as much as digits as its factorization.
155503234147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252000, while the sum is 40.
Adding to 155503234147 its reverse (741432305551), we get a palindrome (896935539698).
The spelling of 155503234147 in words is "one hundred fifty-five billion, five hundred three million, two hundred thirty-four thousand, one hundred forty-seven".
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