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155516000047 = 157990547771
BaseRepresentation
bin1001000011010101111…
…0011101011100101111
3112212102011210100102121
42100311132131130233
510021444044000142
6155235411333411
714143555122022
oct2206536353457
9485364710377
10155516000047
115aa54800681
1226181bb1267
13118852a5a05
1477541b11b9
1540a2eaec67
hex243579d72f

155516000047 has 4 divisors (see below), whose sum is σ = 156506547976. Its totient is φ = 154525452120.

The previous prime is 155516000041. The next prime is 155516000063. The reversal of 155516000047 is 740000615551.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 155516000047 - 227 = 155381782319 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 155515999976 and 155516000021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (155516000041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 495273729 + ... + 495274042.

It is an arithmetic number, because the mean of its divisors is an integer number (39126636994).

Almost surely, 2155516000047 is an apocalyptic number.

155516000047 is a deficient number, since it is larger than the sum of its proper divisors (990547929).

155516000047 is an equidigital number, since it uses as much as digits as its factorization.

155516000047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 990547928.

The product of its (nonzero) digits is 21000, while the sum is 34.

Adding to 155516000047 its reverse (740000615551), we get a palindrome (895516615598).

The spelling of 155516000047 in words is "one hundred fifty-five billion, five hundred sixteen million, forty-seven", and thus it is an aban number.

Divisors: 1 157 990547771 155516000047