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155532141235651 is a prime number
BaseRepresentation
bin100011010111010010100110…
…000001111000110111000011
3202101200201122100012120120111
4203113102212001320313003
5130341214311124020101
61310442251310052151
744521553310323455
oct4327224601706703
9671621570176514
10155532141235651
11456148a1016294
121553b2074aa057
1368a280593ac7b
142a59b1d9722d5
1512eab3436d251
hex8d74a6078dc3

155532141235651 has 2 divisors, whose sum is σ = 155532141235652. Its totient is φ = 155532141235650.

The previous prime is 155532141235547. The next prime is 155532141235661. The reversal of 155532141235651 is 156532141235551.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 155532141235651 - 217 = 155532141104579 is a prime.

It is a super-3 number, since 3×1555321412356513 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 155532141235595 and 155532141235604.

It is not a weakly prime, because it can be changed into another prime (155532141235661) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77766070617825 + 77766070617826.

It is an arithmetic number, because the mean of its divisors is an integer number (77766070617826).

Almost surely, 2155532141235651 is an apocalyptic number.

155532141235651 is a deficient number, since it is larger than the sum of its proper divisors (1).

155532141235651 is an equidigital number, since it uses as much as digits as its factorization.

155532141235651 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2700000, while the sum is 49.

The spelling of 155532141235651 in words is "one hundred fifty-five trillion, five hundred thirty-two billion, one hundred forty-one million, two hundred thirty-five thousand, six hundred fifty-one".