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155540550215 = 531108110043
BaseRepresentation
bin1001000011011011110…
…0000111001001000111
3112212110212222121221002
42100312330013021013
510022021340101330
6155242045443515
714144303601611
oct2206674071107
9485425877832
10155540550215
115aa67649576
122618a27059b
131188a3c023b
147757561db1
1540a520de45
hex2436f07247

155540550215 has 4 divisors (see below), whose sum is σ = 186648660264. Its totient is φ = 124432440168.

The previous prime is 155540550197. The next prime is 155540550241. The reversal of 155540550215 is 512055045551.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-155540550215 is a prime.

It is a super-2 number, since 2×1555405502152 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15554055017 + ... + 15554055026.

It is an arithmetic number, because the mean of its divisors is an integer number (46662165066).

Almost surely, 2155540550215 is an apocalyptic number.

155540550215 is a deficient number, since it is larger than the sum of its proper divisors (31108110049).

155540550215 is an equidigital number, since it uses as much as digits as its factorization.

155540550215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31108110048.

The product of its (nonzero) digits is 125000, while the sum is 38.

Adding to 155540550215 its reverse (512055045551), we get a palindrome (667595595766).

The spelling of 155540550215 in words is "one hundred fifty-five billion, five hundred forty million, five hundred fifty thousand, two hundred fifteen".

Divisors: 1 5 31108110043 155540550215