Base | Representation |
---|---|
bin | 11100111110010101… |
… | …10101100100110001 |
3 | 1111011002002010200011 |
4 | 32133022311210301 |
5 | 223324130220423 |
6 | 11051312254521 |
7 | 1060322016334 |
oct | 163712654461 |
9 | 44132063604 |
10 | 15555320113 |
11 | 6662633263 |
12 | 3021541441 |
13 | 160b8ccc38 |
14 | a77c9a61b |
15 | 610958b0d |
hex | 39f2b5931 |
15555320113 has 2 divisors, whose sum is σ = 15555320114. Its totient is φ = 15555320112.
The previous prime is 15555320107. The next prime is 15555320117. The reversal of 15555320113 is 31102355551.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15103672609 + 451647504 = 122897^2 + 21252^2 .
It is a cyclic number.
It is not a de Polignac number, because 15555320113 - 213 = 15555311921 is a prime.
It is not a weakly prime, because it can be changed into another prime (15555320117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7777660056 + 7777660057.
It is an arithmetic number, because the mean of its divisors is an integer number (7777660057).
Almost surely, 215555320113 is an apocalyptic number.
It is an amenable number.
15555320113 is a deficient number, since it is larger than the sum of its proper divisors (1).
15555320113 is an equidigital number, since it uses as much as digits as its factorization.
15555320113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11250, while the sum is 31.
Adding to 15555320113 its reverse (31102355551), we get a palindrome (46657675664).
The spelling of 15555320113 in words is "fifteen billion, five hundred fifty-five million, three hundred twenty thousand, one hundred thirteen".
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