Base | Representation |
---|---|
bin | 10110101101110011011… |
… | …100110001010001001001 |
3 | 12112020020110210210202112 |
4 | 112231303130301101021 |
5 | 201033422033100441 |
6 | 3153041302512105 |
7 | 220531166332544 |
oct | 26556334612111 |
9 | 5466213723675 |
10 | 1561010050121 |
11 | 552025529015 |
12 | 21264b135635 |
13 | b42831bc292 |
14 | 557a632585b |
15 | 2a9136164eb |
hex | 16b73731449 |
1561010050121 has 2 divisors, whose sum is σ = 1561010050122. Its totient is φ = 1561010050120.
The previous prime is 1561010050043. The next prime is 1561010050139. The reversal of 1561010050121 is 1210500101651.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1524829825600 + 36180224521 = 1234840^2 + 190211^2 .
It is a cyclic number.
It is not a de Polignac number, because 1561010050121 - 218 = 1561009787977 is a prime.
It is a super-2 number, since 2×15610100501212 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1561010050321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 780505025060 + 780505025061.
It is an arithmetic number, because the mean of its divisors is an integer number (780505025061).
Almost surely, 21561010050121 is an apocalyptic number.
It is an amenable number.
1561010050121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1561010050121 is an equidigital number, since it uses as much as digits as its factorization.
1561010050121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 300, while the sum is 23.
Adding to 1561010050121 its reverse (1210500101651), we get a palindrome (2771510151772).
The spelling of 1561010050121 in words is "one trillion, five hundred sixty-one billion, ten million, fifty thousand, one hundred twenty-one".
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