Base | Representation |
---|---|
bin | 100011100001100010100001… |
… | …000001111111001101100011 |
3 | 202111012001112120120000002211 |
4 | 203201202201001333031203 |
5 | 130434234203043342011 |
6 | 1312142005341422551 |
7 | 44623465301206432 |
oct | 4341424101771543 |
9 | 674161476500084 |
10 | 156236432012131 |
11 | 45866553882849 |
12 | 15633800b6aa57 |
13 | 69240560180b3 |
14 | 2a81c52a7d119 |
15 | 130e104e86b21 |
hex | 8e18a107f363 |
156236432012131 has 2 divisors, whose sum is σ = 156236432012132. Its totient is φ = 156236432012130.
The previous prime is 156236432012117. The next prime is 156236432012207. The reversal of 156236432012131 is 131210234632651.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 156236432012131 - 229 = 156235895141219 is a prime.
It is a super-2 number, since 2×1562364320121312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (156236432012231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78118216006065 + 78118216006066.
It is an arithmetic number, because the mean of its divisors is an integer number (78118216006066).
Almost surely, 2156236432012131 is an apocalyptic number.
156236432012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
156236432012131 is an equidigital number, since it uses as much as digits as its factorization.
156236432012131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 40.
Adding to 156236432012131 its reverse (131210234632651), we get a palindrome (287446666644782).
The spelling of 156236432012131 in words is "one hundred fifty-six trillion, two hundred thirty-six billion, four hundred thirty-two million, twelve thousand, one hundred thirty-one".
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