Base | Representation |
---|---|
bin | 1001001000111111100… |
… | …1101100100001101011 |
3 | 120000022220110110102012 |
4 | 2102033321230201223 |
5 | 10033100432323011 |
6 | 200050124030135 |
7 | 14226266143202 |
oct | 2221771544153 |
9 | 500286413365 |
10 | 157033089131 |
11 | 606630a3106 |
12 | 2652609234b |
13 | 11a6769c469 |
14 | 7859882239 |
15 | 4141282a8b |
hex | 248fe6c86b |
157033089131 has 2 divisors, whose sum is σ = 157033089132. Its totient is φ = 157033089130.
The previous prime is 157033089067. The next prime is 157033089137. The reversal of 157033089131 is 131980330751.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 157033089131 - 26 = 157033089067 is a prime.
It is a super-2 number, since 2×1570330891312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (157033089137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78516544565 + 78516544566.
It is an arithmetic number, because the mean of its divisors is an integer number (78516544566).
Almost surely, 2157033089131 is an apocalyptic number.
157033089131 is a deficient number, since it is larger than the sum of its proper divisors (1).
157033089131 is an equidigital number, since it uses as much as digits as its factorization.
157033089131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 41.
The spelling of 157033089131 in words is "one hundred fifty-seven billion, thirty-three million, eighty-nine thousand, one hundred thirty-one".
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