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1572245131 is a prime number
BaseRepresentation
bin101110110110110…
…1000111010001011
311001120110022212011
41131231220322023
511204443321011
6420002400351
753650602022
oct13555507213
94046408764
101572245131
11737545046
1237a6600b7
131c0968982
1410cb4b8b9
159306a621
hex5db68e8b

1572245131 has 2 divisors, whose sum is σ = 1572245132. Its totient is φ = 1572245130.

The previous prime is 1572245111. The next prime is 1572245149. The reversal of 1572245131 is 1315422751.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1572245131 is a prime.

It is a super-2 number, since 2×15722451312 = 4943909503906414322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1572245093 and 1572245102.

It is not a weakly prime, because it can be changed into another prime (1572245111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 786122565 + 786122566.

It is an arithmetic number, because the mean of its divisors is an integer number (786122566).

Almost surely, 21572245131 is an apocalyptic number.

1572245131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1572245131 is an equidigital number, since it uses as much as digits as its factorization.

1572245131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8400, while the sum is 31.

The square root of 1572245131 is about 39651.5463885080. The cubic root of 1572245131 is about 1162.8046312452.

Adding to 1572245131 its reverse (1315422751), we get a palindrome (2887667882).

The spelling of 1572245131 in words is "one billion, five hundred seventy-two million, two hundred forty-five thousand, one hundred thirty-one".