Base | Representation |
---|---|
bin | 1001010011010100000… |
… | …1101000010110010011 |
3 | 120021110222022022221211 |
4 | 2110311001220112103 |
5 | 10104234133103221 |
6 | 201225045400551 |
7 | 14355035366653 |
oct | 2246501502623 |
9 | 507428268854 |
10 | 159803409811 |
11 | 6185494a031 |
12 | 26b79a09157 |
13 | 120b9607676 |
14 | 7a3d77c363 |
15 | 42545a86e1 |
hex | 2535068593 |
159803409811 has 2 divisors, whose sum is σ = 159803409812. Its totient is φ = 159803409810.
The previous prime is 159803409761. The next prime is 159803409847. The reversal of 159803409811 is 118904308951.
It is a strong prime.
It is an emirp because it is prime and its reverse (118904308951) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 159803409811 - 221 = 159801312659 is a prime.
It is a super-2 number, since 2×1598034098112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (159803409011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 79901704905 + 79901704906.
It is an arithmetic number, because the mean of its divisors is an integer number (79901704906).
Almost surely, 2159803409811 is an apocalyptic number.
159803409811 is a deficient number, since it is larger than the sum of its proper divisors (1).
159803409811 is an equidigital number, since it uses as much as digits as its factorization.
159803409811 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 49.
The spelling of 159803409811 in words is "one hundred fifty-nine billion, eight hundred three million, four hundred nine thousand, eight hundred eleven".
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