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15990425400041 is a prime number
BaseRepresentation
bin1110100010110000111110…
…1000000011001011101001
32002121200002020110201202022
43220230033220003023221
54043441342400300131
654001522223114225
73240161435165051
oct350541750031351
962550066421668
1015990425400041
1151055572a5844
121963075142975
138bcb76993751
143d3d25492561
151cae3354c37b
hexe8b0fa032e9

15990425400041 has 2 divisors, whose sum is σ = 15990425400042. Its totient is φ = 15990425400040.

The previous prime is 15990425400029. The next prime is 15990425400071. The reversal of 15990425400041 is 14000452409951.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15984835594816 + 5589805225 = 3998104^2 + 74765^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15990425400041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15990425399965 and 15990425400001.

It is not a weakly prime, because it can be changed into another prime (15990425400071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7995212700020 + 7995212700021.

It is an arithmetic number, because the mean of its divisors is an integer number (7995212700021).

Almost surely, 215990425400041 is an apocalyptic number.

It is an amenable number.

15990425400041 is a deficient number, since it is larger than the sum of its proper divisors (1).

15990425400041 is an equidigital number, since it uses as much as digits as its factorization.

15990425400041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 44.

Adding to 15990425400041 its reverse (14000452409951), we get a palindrome (29990877809992).

The spelling of 15990425400041 in words is "fifteen trillion, nine hundred ninety billion, four hundred twenty-five million, four hundred thousand, forty-one".