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16000017443143 = 54013929622037
BaseRepresentation
bin1110100011010100101101…
…0110110010100101000111
32002122120211201121000012221
43220311023112302211013
54044121013431140033
654010150113553211
73240651230205226
oct350651326624507
962576751530187
1016000017443143
1151096297aa798
121964ab1575807
138c0a44cb49b6
143d459537ccbd
151cb2e56c412d
hexe8d4b5b2947

16000017443143 has 4 divisors (see below), whose sum is σ = 16000047605320. Its totient is φ = 15999987280968.

The previous prime is 16000017443131. The next prime is 16000017443159. The reversal of 16000017443143 is 34134471000061.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 16000017443143 - 221 = 16000015345991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16000017443099 and 16000017443108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (16000017443183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14270880 + ... + 15351157.

It is an arithmetic number, because the mean of its divisors is an integer number (4000011901330).

Almost surely, 216000017443143 is an apocalyptic number.

16000017443143 is a deficient number, since it is larger than the sum of its proper divisors (30162177).

16000017443143 is an equidigital number, since it uses as much as digits as its factorization.

16000017443143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30162176.

The product of its (nonzero) digits is 24192, while the sum is 34.

The spelling of 16000017443143 in words is "sixteen trillion, seventeen million, four hundred forty-three thousand, one hundred forty-three".

Divisors: 1 540139 29622037 16000017443143