Base | Representation |
---|---|
bin | 10111010011001001110… |
… | …001100101000000001011 |
3 | 12200001202022200100002211 |
4 | 113103021301211000023 |
5 | 202213034420114042 |
6 | 3223312521205551 |
7 | 223451034245101 |
oct | 27231161450013 |
9 | 5601668610084 |
10 | 1601113051147 |
11 | 568034638275 |
12 | 21a3816308b7 |
13 | b7ca46c629c |
14 | 576cc465c71 |
15 | 2b9ae197017 |
hex | 174c9c6500b |
1601113051147 has 2 divisors, whose sum is σ = 1601113051148. Its totient is φ = 1601113051146.
The previous prime is 1601113051127. The next prime is 1601113051303. The reversal of 1601113051147 is 7411503111061.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1601113051147 - 231 = 1598965567499 is a prime.
It is not a weakly prime, because it can be changed into another prime (1601113051127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 800556525573 + 800556525574.
It is an arithmetic number, because the mean of its divisors is an integer number (800556525574).
Almost surely, 21601113051147 is an apocalyptic number.
1601113051147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1601113051147 is an equidigital number, since it uses as much as digits as its factorization.
1601113051147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 31.
The spelling of 1601113051147 in words is "one trillion, six hundred one billion, one hundred thirteen million, fifty-one thousand, one hundred forty-seven".
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