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16014113 is a prime number
BaseRepresentation
bin111101000101…
…101100100001
31010010121020022
4331011230201
513044422423
61331123225
7253055243
oct75055441
933117208
1016014113
119048705
125443515
13341910b
1421ac093
151614dc8
hexf45b21

16014113 has 2 divisors, whose sum is σ = 16014114. Its totient is φ = 16014112.

The previous prime is 16014077. The next prime is 16014133. The reversal of 16014113 is 31141061.

16014113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10387729 + 5626384 = 3223^2 + 2372^2 .

It is a cyclic number.

It is not a de Polignac number, because 16014113 - 212 = 16010017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16014091 and 16014100.

It is not a weakly prime, because it can be changed into another prime (16014133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8007056 + 8007057.

It is an arithmetic number, because the mean of its divisors is an integer number (8007057).

Almost surely, 216014113 is an apocalyptic number.

It is an amenable number.

16014113 is a deficient number, since it is larger than the sum of its proper divisors (1).

16014113 is an equidigital number, since it uses as much as digits as its factorization.

16014113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 16014113 is about 4001.7637361543. The cubic root of 16014113 is about 252.0582768135.

Adding to 16014113 its reverse (31141061), we get a palindrome (47155174).

The spelling of 16014113 in words is "sixteen million, fourteen thousand, one hundred thirteen".