Base | Representation |
---|---|
bin | 10111010011111101010… |
… | …110100110010110010111 |
3 | 12200010222121222022100101 |
4 | 113103331112212112113 |
5 | 202221322432102012 |
6 | 3223534432354531 |
7 | 223511342450425 |
oct | 27237526462627 |
9 | 5603877868311 |
10 | 1601978394007 |
11 | 568439049162 |
12 | 21a5833a5a47 |
13 | b80b1a76c94 |
14 | 57771360115 |
15 | 2ba10129d57 |
hex | 174fd5a6597 |
1601978394007 has 4 divisors (see below), whose sum is σ = 1636063040736. Its totient is φ = 1567893747280.
The previous prime is 1601978393999. The next prime is 1601978394103. The reversal of 1601978394007 is 7004938791061.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1601978394007 - 23 = 1601978393999 is a prime.
It is a super-3 number, since 3×16019783940073 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1601978394607) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17042323294 + ... + 17042323387.
It is an arithmetic number, because the mean of its divisors is an integer number (409015760184).
Almost surely, 21601978394007 is an apocalyptic number.
1601978394007 is a deficient number, since it is larger than the sum of its proper divisors (34084646729).
1601978394007 is an equidigital number, since it uses as much as digits as its factorization.
1601978394007 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34084646728.
The product of its (nonzero) digits is 2286144, while the sum is 55.
The spelling of 1601978394007 in words is "one trillion, six hundred one billion, nine hundred seventy-eight million, three hundred ninety-four thousand, seven".
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