Base | Representation |
---|---|
bin | 11101111000000000… |
… | …11101101001011101 |
3 | 1112101210110201200202 |
4 | 32330000131221131 |
5 | 230322004434213 |
6 | 11211314233245 |
7 | 1105315303625 |
oct | 167400355135 |
9 | 45353421622 |
10 | 16039139933 |
11 | 6890749253 |
12 | 3137585825 |
13 | 1687c0b45b |
14 | ac223d885 |
15 | 63d177b58 |
hex | 3bc01da5d |
16039139933 has 4 divisors (see below), whose sum is σ = 16039676988. Its totient is φ = 16038602880.
The previous prime is 16039139917. The next prime is 16039139947. The reversal of 16039139933 is 33993193061.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6691730809 + 9347409124 = 81803^2 + 96682^2 .
It is a cyclic number.
It is not a de Polignac number, because 16039139933 - 24 = 16039139917 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16039139903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220916 + ... + 284397.
It is an arithmetic number, because the mean of its divisors is an integer number (4009919247).
Almost surely, 216039139933 is an apocalyptic number.
It is an amenable number.
16039139933 is a deficient number, since it is larger than the sum of its proper divisors (537055).
16039139933 is an equidigital number, since it uses as much as digits as its factorization.
16039139933 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 537054.
The product of its (nonzero) digits is 354294, while the sum is 47.
The spelling of 16039139933 in words is "sixteen billion, thirty-nine million, one hundred thirty-nine thousand, nine hundred thirty-three".
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