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1604474604553 is a prime number
BaseRepresentation
bin10111010110010010001…
…000111000110000001001
312200101102121000221110211
4113112102020320300021
5202241430444321203
63225030243041121
7223630243054252
oct27262210706011
95611377027424
101604474604553
115694aa0a4087
1221ab5b3701a1
13b83bbc7a642
145792aaa5b29
152bb09357c6d
hex17592238c09

1604474604553 has 2 divisors, whose sum is σ = 1604474604554. Its totient is φ = 1604474604552.

The previous prime is 1604474604539. The next prime is 1604474604619. The reversal of 1604474604553 is 3554064744061.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1573087875984 + 31386728569 = 1254228^2 + 177163^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1604474604553 is a prime.

It is a super-3 number, since 3×16044746045533 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1604474604497 and 1604474604506.

It is not a weakly prime, because it can be changed into another prime (1604474604503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 802237302276 + 802237302277.

It is an arithmetic number, because the mean of its divisors is an integer number (802237302277).

Almost surely, 21604474604553 is an apocalyptic number.

It is an amenable number.

1604474604553 is a deficient number, since it is larger than the sum of its proper divisors (1).

1604474604553 is an equidigital number, since it uses as much as digits as its factorization.

1604474604553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4838400, while the sum is 49.

The spelling of 1604474604553 in words is "one trillion, six hundred four billion, four hundred seventy-four million, six hundred four thousand, five hundred fifty-three".