Base | Representation |
---|---|
bin | 1110101000001110101100… |
… | …1000101010110000101011 |
3 | 2002221122101200202012212221 |
4 | 3222003223020222300223 |
5 | 4102011122413134113 |
6 | 54113005422414511 |
7 | 3250024003150051 |
oct | 352035310526053 |
9 | 62848350665787 |
10 | 16084302474283 |
11 | 514135048011a |
12 | 19792b4431437 |
13 | 8c8987ac78a4 |
14 | 3d86ad2661d1 |
15 | 1cd5c9e6b98d |
hex | ea0eb22ac2b |
16084302474283 has 2 divisors, whose sum is σ = 16084302474284. Its totient is φ = 16084302474282.
The previous prime is 16084302474223. The next prime is 16084302474293. The reversal of 16084302474283 is 38247420348061.
It is a strong prime.
It is an emirp because it is prime and its reverse (38247420348061) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16084302474283 - 217 = 16084302343211 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 16084302474283.
It is not a weakly prime, because it can be changed into another prime (16084302474223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8042151237141 + 8042151237142.
It is an arithmetic number, because the mean of its divisors is an integer number (8042151237142).
Almost surely, 216084302474283 is an apocalyptic number.
16084302474283 is a deficient number, since it is larger than the sum of its proper divisors (1).
16084302474283 is an equidigital number, since it uses as much as digits as its factorization.
16084302474283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6193152, while the sum is 52.
The spelling of 16084302474283 in words is "sixteen trillion, eighty-four billion, three hundred two million, four hundred seventy-four thousand, two hundred eighty-three".
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