161132235704471 has 4 divisors (see below), whose sum is σ = 161132261140200. Its totient is φ = 161132210268744.

The previous prime is 161132235704443. The next prime is 161132235704527. The reversal of 161132235704471 is 174407532231161.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-161132235704471 is a prime.

It is a super-3 number, since 3×161132235704471³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (161132235764471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5185640 + ... + 18685698.

It is an arithmetic number, because the mean of its divisors is an integer number (40283065285050).

Almost surely, 2^{161132235704471} is an apocalyptic number.

161132235704471 is a deficient number, since it is larger than the sum of its proper divisors (25435729).

161132235704471 is a wasteful number, since it uses less digits than its factorization.

161132235704471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25435728.

The product of its (nonzero) digits is 846720, while the sum is 47.

The spelling of 161132235704471 in words is "one hundred sixty-one trillion, one hundred thirty-two billion, two hundred thirty-five million, seven hundred four thousand, four hundred seventy-one".