Base | Representation |
---|---|
bin | 11110000000111000… |
… | …10000100111001001 |
3 | 1112120222110102010122 |
4 | 33000130100213021 |
5 | 231000031113213 |
6 | 11222532553025 |
7 | 1110210535262 |
oct | 170034204711 |
9 | 45528412118 |
10 | 16113535433 |
11 | 6919741736 |
12 | 3158482775 |
13 | 169a458868 |
14 | acc087969 |
15 | 644970d08 |
hex | 3c07109c9 |
16113535433 has 2 divisors, whose sum is σ = 16113535434. Its totient is φ = 16113535432.
The previous prime is 16113535393. The next prime is 16113535457. The reversal of 16113535433 is 33453531161.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11670913024 + 4442622409 = 108032^2 + 66653^2 .
It is a cyclic number.
It is not a de Polignac number, because 16113535433 - 28 = 16113535177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16113535393 and 16113535402.
It is not a weakly prime, because it can be changed into another prime (16115535433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8056767716 + 8056767717.
It is an arithmetic number, because the mean of its divisors is an integer number (8056767717).
Almost surely, 216113535433 is an apocalyptic number.
It is an amenable number.
16113535433 is a deficient number, since it is larger than the sum of its proper divisors (1).
16113535433 is an equidigital number, since it uses as much as digits as its factorization.
16113535433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48600, while the sum is 35.
The spelling of 16113535433 in words is "sixteen billion, one hundred thirteen million, five hundred thirty-five thousand, four hundred thirty-three".
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