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161201102113 is a prime number
BaseRepresentation
bin1001011000100001010…
…1011001110100100001
3120102002101022110100101
42112020111121310201
510120114440231423
6202015455022401
714434466521432
oct2261025316441
9512071273311
10161201102113
1162401901a37
12272a9b0aa01
131228005892c
147b3324d489
1542d71447ad
hex2588559d21

161201102113 has 2 divisors, whose sum is σ = 161201102114. Its totient is φ = 161201102112.

The previous prime is 161201102063. The next prime is 161201102149. The reversal of 161201102113 is 311201102161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 159945604624 + 1255497489 = 399932^2 + 35433^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-161201102113 is a prime.

It is a super-3 number, since 3×1612011021133 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (161201112113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80600551056 + 80600551057.

It is an arithmetic number, because the mean of its divisors is an integer number (80600551057).

Almost surely, 2161201102113 is an apocalyptic number.

It is an amenable number.

161201102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

161201102113 is an equidigital number, since it uses as much as digits as its factorization.

161201102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 161201102113 its reverse (311201102161), we get a palindrome (472402204274).

The spelling of 161201102113 in words is "one hundred sixty-one billion, two hundred one million, one hundred two thousand, one hundred thirteen".