16120120433 has 2 divisors, whose sum is σ = 16120120434. Its totient is φ = 16120120432.

The previous prime is 16120120427. The next prime is 16120120441. The reversal of 16120120433 is 33402102161.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8337881344 + 7782239089 = 91312^2 + 88217^2 .

It is an emirp because it is prime and its reverse (33402102161) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16120120433 - 2¹⁰ = 16120119409 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 16120120399 and 16120120408.

It is not a weakly prime, because it can be changed into another prime (16120120483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8060060216 + 8060060217.

It is an arithmetic number, because the mean of its divisors is an integer number (8060060217).

Almost surely, 2^16120120433 is an apocalyptic number.

It is an amenable number.

16120120433 is a deficient number, since it is larger than the sum of its proper divisors (1).

16120120433 is an equidigital number, since it uses as much as digits as its factorization.

16120120433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 16120120433 its reverse (33402102161), we get a palindrome (49522222594).

The spelling of 16120120433 in words is "sixteen billion, one hundred twenty million, one hundred twenty thousand, four hundred thirty-three".