Base | Representation |
---|---|
bin | 1001011000101110010… |
… | …0010100100100100001 |
3 | 120102020011101020210121 |
4 | 2112023210110210201 |
5 | 10120222332010132 |
6 | 202025113400241 |
7 | 14436025545316 |
oct | 2261344244441 |
9 | 512204336717 |
10 | 161255344417 |
11 | 6242a48aa92 |
12 | 27304109081 |
13 | 1228b36ac7b |
14 | 7b3a52cd0d |
15 | 42dbcab497 |
hex | 258b914921 |
161255344417 has 2 divisors, whose sum is σ = 161255344418. Its totient is φ = 161255344416.
The previous prime is 161255344409. The next prime is 161255344463. The reversal of 161255344417 is 714443552161.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 160295336161 + 960008256 = 400369^2 + 30984^2 .
It is a cyclic number.
It is not a de Polignac number, because 161255344417 - 23 = 161255344409 is a prime.
It is a super-2 number, since 2×1612553444172 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (161255344487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80627672208 + 80627672209.
It is an arithmetic number, because the mean of its divisors is an integer number (80627672209).
Almost surely, 2161255344417 is an apocalyptic number.
It is an amenable number.
161255344417 is a deficient number, since it is larger than the sum of its proper divisors (1).
161255344417 is an equidigital number, since it uses as much as digits as its factorization.
161255344417 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 403200, while the sum is 43.
Adding to 161255344417 its reverse (714443552161), we get a palindrome (875698896578).
The spelling of 161255344417 in words is "one hundred sixty-one billion, two hundred fifty-five million, three hundred forty-four thousand, four hundred seventeen".
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