Base | Representation |
---|---|
bin | 110000000100011… |
… | …0011100111111101 |
3 | 11011101222220010110 |
4 | 1200020303213331 |
5 | 11300401440331 |
6 | 424014300233 |
7 | 54653414403 |
oct | 14010634775 |
9 | 4141886113 |
10 | 1612921341 |
11 | 7584a7749 |
12 | 3901b7679 |
13 | 1c920b235 |
14 | 1142d9473 |
15 | 96902946 |
hex | 602339fd |
1612921341 has 4 divisors (see below), whose sum is σ = 2150561792. Its totient is φ = 1075280892.
The previous prime is 1612921339. The next prime is 1612921361. The reversal of 1612921341 is 1431292161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1612921341 - 21 = 1612921339 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1612921299 and 1612921308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1612921301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268820221 + ... + 268820226.
It is an arithmetic number, because the mean of its divisors is an integer number (537640448).
Almost surely, 21612921341 is an apocalyptic number.
It is an amenable number.
1612921341 is a deficient number, since it is larger than the sum of its proper divisors (537640451).
1612921341 is an equidigital number, since it uses as much as digits as its factorization.
1612921341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 537640450.
The product of its digits is 2592, while the sum is 30.
The square root of 1612921341 is about 40161.1919768326. The cubic root of 1612921341 is about 1172.7471766549.
The spelling of 1612921341 in words is "one billion, six hundred twelve million, nine hundred twenty-one thousand, three hundred forty-one".
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