Base | Representation |
---|---|
bin | 1110101010111001000010… |
… | …0111110110001110011011 |
3 | 2010010000102102110010002121 |
4 | 3222232100213312032123 |
5 | 4103233244302430212 |
6 | 54150011031242111 |
7 | 3253233100400113 |
oct | 352562047661633 |
9 | 63100372403077 |
10 | 16130028561307 |
11 | 5159785683091 |
12 | 1986135b19337 |
13 | 90009428000b |
14 | 3da9aa100043 |
15 | 1ce8a44d1d07 |
hex | eab909f639b |
16130028561307 has 2 divisors, whose sum is σ = 16130028561308. Its totient is φ = 16130028561306.
The previous prime is 16130028561299. The next prime is 16130028561319. The reversal of 16130028561307 is 70316582003161.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16130028561307 - 23 = 16130028561299 is a prime.
It is not a weakly prime, because it can be changed into another prime (16130028561337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8065014280653 + 8065014280654.
It is an arithmetic number, because the mean of its divisors is an integer number (8065014280654).
Almost surely, 216130028561307 is an apocalyptic number.
16130028561307 is a deficient number, since it is larger than the sum of its proper divisors (1).
16130028561307 is an equidigital number, since it uses as much as digits as its factorization.
16130028561307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 43.
The spelling of 16130028561307 in words is "sixteen trillion, one hundred thirty billion, twenty-eight million, five hundred sixty-one thousand, three hundred seven".
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