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161330033471 = 213349756179
BaseRepresentation
bin1001011001000000000…
…1001111001100111111
3120102102100220211220212
42112100001033030333
510120400442032341
6202040342303035
714440623441545
oct2262001171477
9512370824825
10161330033471
1162468663a82
1227325127a7b
13122a098bb89
147b46411d95
1542e36115eb
hex259004f33f

161330033471 has 4 divisors (see below), whose sum is σ = 161331003000. Its totient is φ = 161329063944.

The previous prime is 161330033461. The next prime is 161330033477. The reversal of 161330033471 is 174330033161.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-161330033471 is a prime.

It is a super-3 number, since 3×1613300334713 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (161330033477) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164741 + ... + 591438.

It is an arithmetic number, because the mean of its divisors is an integer number (40332750750).

Almost surely, 2161330033471 is an apocalyptic number.

161330033471 is a deficient number, since it is larger than the sum of its proper divisors (969529).

161330033471 is an equidigital number, since it uses as much as digits as its factorization.

161330033471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 969528.

The product of its (nonzero) digits is 13608, while the sum is 32.

The spelling of 161330033471 in words is "one hundred sixty-one billion, three hundred thirty million, thirty-three thousand, four hundred seventy-one".

Divisors: 1 213349 756179 161330033471